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TM 38-400/NAVSUP PUB 572/AFMAN 23-210 MCO 4450.14/DLAM 4145.12
R
=
48
x
5-120(min)
=
1 fork truck
2
(2) In the same operation, a requirement exists to
move 192 pallets the same distance in the same time
frame.
R
=
192
x
5-120
=
4forktrucks
2
(3) A requirement exists to relocate 4,064 pallet loads a
4-29. Computing Pallet Requirements.
distance of 1,500 feet. Time allotted is 3 days. Since
the distance is greater than 400 feet (max travel
a. The investment in pallets.
This can be
distance of fork truck), tractor trains are required. One
substantial and should be based upon definite
tractor and 4 trailers carry 8 pallets in a 20-minute round
requirements. The standard pallet is 40 by 48 inches.
trip cycle. It takes 5 minutes for 1 forklift truck to load a
Allowing for overhang (roughly 25 pct), the square feet
train and 8 minutes to unload and stack.
occupied by each pallet is approximately 16 feet (4 by 4
ft). If height permits stacking 4 pallets high, 4 pallets
Step 1
are required for each 16 square feet of net usable floor
Computer pieces of equipment required.
space.
R = 4,064 pallets x 0.33 hrs (20 min) - 24 hrs
b. Not all space is usable. Roof supports, aisles,
8 pallets/train
mechanical equipment required for the building, and
= 7 tractors
other structural losses reduce the gross space to net
Step 2
usable space which should be the basis for computing
7 trailer trains x 5 min - 20 min
pallets.
1 trailer train
c. Percent of occupancy is another consideration.
= 2 forklift trucks for loading
Assuming a goal of 85 percent occupancy of net space
Step 3
is a target, the following is an example of use of the
7 trailer trains x 8 - 20
formula shown in figure 4-106: Compute the pallet
1 trailer train
requirements for 100,000 gross square feet of storage
= 3 forklift trucks for unloading/stacking
space, 70 percent net usable and 85 percent occupancy
with stacking 4 pallets high.
The entire operation will take 7 tractors, 28 trailers (4
trailers per tractor), and 5 forklift trucks with 12
operators to complete the job in 3 days.
R
=
(100,000
x
70x.85)x4
=
14,875 pallets.
16
4-71
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